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Problems On Trains Quiz Details
Quiz Name
Problems On Trains
Category
Online Aptitude Test
Number of Questions
30
Time
30 Minutes
Exam Type
MCQ (Multiple Choice Questions)
Problems On Trains Online Test
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1. A train travelling at 60 kilometres per hour crosses a pole in 9 seconds. What is the train's duration?
a.120 metres
b. 180 metres
c. 324 metres
d. 150 metres
Answer: D
Explanation:
Speed = 60/18 x 5 m/sec = 50/3 m/sec.The train's length equals (Speed x Time).
50/3 x 9 m = 150 m is the train's length.
2. In 10 seconds, a 125-meter-long train passes a man jogging at 5 km/hr in the same direction as the train. The train's top speed is
a. 45 km/hr
b. 50 km/hr
c. 54 km/hr
d. 55 km/hr
Answer: B
Explanation:
Train speed in relation to man = 125/10 m/sec= 25/2 m/sec.= 25/2 x 18/5 km/hr,45 km/hr is a speed of 45 km/hr.Let's say the train's speed is x km/hr. The relative speed is then equal to (x - 5) km/hr, x - 5 km/hr = 45, x = 50 km/hr
3. The bridge is 130 metres long and can be crossed in 30 seconds by a train travelling at 45 kilometres per hour.
a. 200 m
b. 225 m
c. 245 m
d. 250 m
Answer: C
Explanation:
45 x 5/18 m/sec = 25/2 m/sec. Allow 30 seconds and a bridge length of x metres.
As a result, 130 + x/30 = 25/2= 2(130 + x) = 750 , x = 245 m.
4. In 27 seconds and 17 seconds, two trains going in different directions cross a man standing on the platform, and they cross each other in 23 seconds. The following is the ratio of their speeds:
a. 1 : 3
b. 3 : 2
c. 3 : 4
d. None of these
Answer: B
Explanation:
5. In 36 seconds, a train passes a station platform, while a man standing on the platform takes 20 seconds. What is the length of the platform if the train is travelling at 54 km/h?
a. 120 m
b. 240 m
c. 300 m
d. None of these
Answer: B
Explanation:
54 m/sec x 5/18 m/sec = 15 m/sec.The train's length is calculated as (15 x 20)m = 300 m.Let the platform's length be x metres.After that, x + 300/36 = 15, 540 = x + 300,x = 240 metres
6. It takes 24 seconds for a train of 240 metres to pass a pole. How long will it take to pass a 650-meter platform?
a. 65 sec
b. 89 sec
c. 100 sec
d. 150 sec
7. At 46 km/hr and 36 km/hr, two trains of equal length are travelling in the same direction on parallel tracks. In 36 seconds, the quicker train passes the slower train. Each train is the following length:
a. 50 m
b. 72 m
c. 80 m
d. 82 m
Answer: A
Explanation:
Let each train be x metres long.Then the distance covered is equal to 2x metres.
(46 - 36) km/hr= 10 x 5/18 m/s= 25/9 m/secAs a result, 2x/36 = 25/9, 100 = 2x.x equals fifty.
8. A train with a length of 360 metres is travelling at a speed of 45 kilometres per hour. How long will it take to cross a 140-meter bridge?
a. 40 sec
b. 42 sec
c. 45 sec
d. 48 sec
Answer: A
Explanation:
To convert km/hr to m/s, use the formula X km/hr = X x 5/18 m/s.As a result, Speed = 45 x 5/18 m/sec = 25/2 m/sec.(360 + 140) m = 500 m is the total distance to be travelled.Time = Distance / Speed Required time = 500 x 2/25 sec = 40 sec
9. Two trains are travelling at 60 km/hr and 90 km/hr in opposite directions. Their respective lengths are 1.10 kilometres and 0.9 km. The slower train takes the following time in seconds to cross the quicker train:
a. 36
b. 45
c. 48
d. 49
Answer: C
Explanation:
(60+ 90) km/hr = 150 x 5/18 m/sec = 125/3 m/sec, Relative speed = (60+ 90) km/hr
(1.10 + 0.9) km = 2 km = 2000 m is the distance covered.Time required = 2000 x 3/125 sec = 48 sec
10. A runner running at 9 kilometres per hour runs alongside a railway track 240 metres ahead of the engine of a 120-meter-long train travelling at 45 kilometres per hour in the same direction. How long will the train take to pass the jogger?
a. 3.6 sec
b. 18sec
c. 36sec
d. 72 sec
Answer: C
Explanation:
The train's speed in relation to the runner is (45 - 9) km/hr, or 36 km/hr.
10 m/sec = 36 x 5/18 m/sec.(240 + 120) m = 360 m is the distance to be covered.1 minute = 360/10 seconds = 36 seconds
11. In 9 seconds, a 270-meter-long train travelling at 120 kmph crosses another train travelling at 80 kmph in the other direction. What is the other train's length?
a. 230 m
b. 240 m
c. 260 m
d. 720 m
Answer: A
Explanation:
Relative speed equals (120 + 80) km/hr = 200 x 5/18 m/sec = 500/9 m/sec.Let the other train's length be x metres.As a result, x + 270/9 = 500/9 x + 270 = 500 x = 230.
12. A 72-kilometer-per-hour goods train passes a 250-meter-long platform in 26 seconds. What is the freight train's length?
a. 230 m
b. 240 m
c. 260 m
d. 270 m
Answer: D
Explanation:
Speed = 72 x 5/18 m/sec = 20 m/sec (explanation).Let's say the train's length is x metres and the time is 26 seconds.As a result, x + 250/26 = 20, x + 250 = 520, x = 270.
13. In 8 seconds, two trains, each 100 metres long and going in opposite directions, cross each other. If one train travels twice as fast as the other, the faster train's speed is:
a. 30 km/hr
b. 45 km/hr
c. 60 km/hr
d. 75 km/hr
Answer: C
Explanation:
Let the slower train's speed be x m/sec.The faster train's speed is then 2x m/sec.(x + 2x) m/sec = 3x m/sec is the relative speed.3x (100 + 100)/8=200 divided by 24=25/3 is the value of x.
As a result, the quicker train's speed is 50/3 m/sec.= 50/3 x 18/5 km/hr.60 km/hr is a speed of 60 km/hr.
14. Two trains, 140 m and 160 m long, run in opposite directions on parallel lines at 60 km/hr and 40 km/hr, respectively. The time it takes them to cross each other in seconds is:
a. 9
b. 9.6
c. 10
d. 10.8
Answer: D
Explanation:
100 x 5/18 m/sec = 250/9 m/sec= Relative speed = (60 + 40) km/hr,(140 + 160) m = 300 m is the distance traversed when they cross each other.Time required = 300 x 9/250 sec = 54/5 sec = 10.8 sec
15. A train with a length of 110 metres is travelling at a speed of 60 kilometres per hour. What time will it pass a man jogging at 6 kmph in the opposite direction as the train?
a. 5 sec
b. 6 sec
c. 7 sec
d. 10 sec
Answer: B
Explanation:
The train's speed in relation to the man is (60 + 6) km/hr = 66 km/hr.66 × 5/18 m/sec = 66 x 5/18 m/sec= 55/33 m/sec.The time it took to pass the man was 110 x 3/55 = 6 seconds.
16. A train travelling at 75 miles per hour enters a 3 1/2-mile tunnel. The train is about a quarter mile long. From the time the train enters the tunnel to the time it emerges, how long does it take for the train to pass through
a. 2.5 min
b. 3 min
c. 3.2 min
d. 3.5 min
Answer: B
Explanation:
The total distance covered is ( 7/2 + 1/4 ) miles, which is 15/4 miles.
As a result, Time taken = ( 15/4 x 75 ) hrs = 1/20 hrs = ( 1/20 x 60 ) min. = 3 min.
17. A train 800 metres long is travelling at 78 kilometres per hour. If it travels through a tunnel in one minute, the tunnel's length (in metres) is
a. 130
b. 360
c. 500
d. 540
Answer: C
Explanation:
Speed = ( 78 x 5/18 m/sec ) m/sec = ( 65/3 ) m/sec.1 minute equals 60 seconds.
Let's say the tunnel is x metres long.As a result, ( 800 + x/60 ) = 65/3, 3 x (800 + x)=3900
=> x equals 500.
18. A 300-meter train takes 39 seconds to cross a platform and 18 seconds to traverse a signal pole. What is the platform's length?
a. 320 m
b. 350 m
c. 650 m
d. Data inadequate
Answer: B
Explanation:
Speed equals ( 300/18 ) m/sec, which equals 50/3 m/sec.
Let the platform's length be x metres.Then ( x + 300/39 ) = 50/3, which equals 3(x + 300) = 1950, which equals x = 350 m.
19. A train can pass a pole in 15 seconds and a 100-meter platform in 25 seconds. It has the following length:
a. 50 m
b. 150 m
c. 200 m
d. Data inadequate
Answer: B
Explanation:
Assume the train is x metres long and travels at y metres per second.Consequently, x/y = 15 => y = x/15. x + 100/25 Equals x/15 as a result.=> 25x = 15(x + 100).=> 15 times + 1500 times = 25 times=> 1500 multiplied by ten is equal to a tenfold increase.=> 150 m is the value of x.
20. In 8 seconds and 20 seconds, a train passes by a telegraph post and a 264-meter-long bridge, respectively. What is the train's top speed?
a. 69.5 km/hr
b. 70 km/hr
c. 79 km/hr
d. 79.2 km/hr
Answer: D
Explanation:
Assume the train's length is x metres and its speed is y metres per second.Then, x/y = 8 => x = 8y; now, x + 264/20 = y => 8y + 264 = 20y => y = 22; now, x + 264/20 = y => 8y + 264 = 20y => y = 22.As a result, Speed = 22 m/sec equals ( 22 x 18/5 ) km/hr = 79.2 km/hr.
21. If the train's speed is 63 km/hr, how long will it take a 500 metre long train to cross a man walking at 3 km/hr in the direction of the moving train?
a. 25
b. 30
c. 40
d. 45
Answer: B
Explanation:
The train's speed in relation to the man is (63 - 3) km/hr = 60 km/hr = (60 x 5/18 ) m/sec
= ( 50/3 ) m/sec.As a result, the time it takes to pass the man is ( 500 x 3/50 ) seconds = 30 seconds.
22. On parallel lines, two goods trains, each 500 metres long, are travelling in opposing directions. Their respective top speeds are 45 km/hr and 30 km/hr. Calculate the time it takes the slower train to pass the faster train's driver.
a. 12 sec
b. 24 sec
c. 48 sec
d. 60 sec
Answer: B
Explanation:
(75 x 5/18 ) m/sec = relative speed = (45 + 30) km/hr= ( 125/6 ) m/sec.
We need to calculate the time it takes the slower train to pass the faster train's DRIVER, not the entire train.As a result, the distance travelled equals the length of the slower train.As a result, the distance covered is 500 metres.As a result, the required time is ( 500 x 6) = 24 seconds.
23. Two trains are travelling at the same speed in different directions. If each train is 120 metres long and crosses in 12 seconds, the speed of each train (in kilometres per hour) is:
a. 10
b. 18
c. 36
d. 72
Answer: C
Explanation:
Assume that each train travels at a speed of x m/sec.Then the two trains' relative speed equals 2x m/sec.As a result, 2x = (120 + 120/12) => 2x = 20 => x = 10.As a result, each train's speed is 10 m/sec, which equals ( 10 x 18/5) km/hr, or 36 km/hr.
24. It takes 10 seconds and 15 seconds for two trains of similar length to cross a telegraph post. If each train is 120 metres long, how long will it take for them to cross in the opposite direction (in seconds)?
a. 10
b. 12
c. 15
d. 20
Answer: B
Explanation:
The first train's speed is ( 120/10 ) m/sec, or 12 m/sec.The second train's speed is ( 120/15 ) m/sec, or 8 m/sec.(12 + 8) = 20 m/sec relative speedAs a result, the required time is [ (120 + 120)/20 ].12 seconds equals sec.
25. In 6 seconds, a train 108 metres long travelling at 50 kilometres per hour crosses a train 112 metres long travelling in the other direction. The second train travels at the following speed:
a. 48 km/hr
b. 54 km/hr
c. 66 km/hr
d. 82 km/hr
Answer: D
Explanation:
Let the second train's speed be x km/hr ,[ (x + 50) x 5/18 ] m/sec 18 = [ 250 + 5x ]/18 m/sec Relative speed = (x + 50) km/hr = [ (x + 50) x 5/18 ] m/sec = [ 250 + 5x ]/18 m/sec.(108 + 112) = 220 m is the total distance covered.As a result, 220/(250 + 5x)/18 = 6=> 660 = 250 + 5x=> x is equal to 82 km/hr.
26. In the same direction, two trains are travelling at 40 km/hr and 20 km/hr, respectively. In less than 5 seconds, a fast train passes a man on a slower train. What is the fast train's duration?
a. 23 m
b. 23 2/9 m
c. 27 7/9 m
d. 29 m
Answer: C
Explanation:
(40 - 20) km/hr = ( 20 x 5/18 ) m/sec = ( 50/9) m/sec
As a result, the length of the speedier train is ( 50 x 5/9) m = 250/9 m = 27x7/9 m.
27. A train passes two people walking in the same direction as the train at speeds of 2 and 4 kilometres per hour, passing them entirely in 9 and 10 seconds, respectively. The train is the following length
a. 45 m
b. 50 m
c. 54 m
d. 72 m
Answer: B
Explanation:
( 2 x 5/18 )m/sec = 5/9 m/sec) = 2 kmph,( 4 x 5/18 ) m/sec = 10/9 m/sec) = 4 kmph
Let the train's length be x metres and its speed be y metres per second.Then (x/y -5/9) equals 9 and (x/y -10/9) equals 10.As a result, 9y minus 5 equals x, and 10(9y minus 10) equals 9x.=>
90y - 9x = 100 and 9y - x = 5.When we solve the problem, we get x = 50.As a result, the train's length is 50 metres.
28. Two people strolling along a railway track are overtaken by a train. The first one walks at a speed of 4.5 kilometres per hour. The other walks at a speed of 5.4 km/hr. The train takes 8.4 and 8.5 seconds to pass them, respectively. If both people are walking in the same direction as the train, what is the train's speed?
a. 66 km/hr
b. 72 km/hr
c. 78 km/hr
d. 81 km/hr
Answer: D
Explanation:
4.5 km/hr equals (4.5 x 5/18 ) m/sec = 5/4 m/sec = 1.25 m/sec, while 5.4 km/hr equals (5.4 x 5/18 ) m/sec = 3/2 m/sec = 1.5 m/sec.Let's say the train's speed is x m/sec.Consequently, (x - 1.25) x 8.4 = (x - 1.5) x 8.5 => 8.4x - 10.5 = 8.5x - 12.75 => 0.1x = 2.25 => x = 22.5.As a result, the train's speed is ( 22.5 x 18/5 ) km/hr = 81 km/hr.
29. In 12 seconds, a train travelling at 48 kilometres per hour crosses another train travelling in the opposite direction at 42 kilometres per hour. It also takes 45 seconds to pass a railway platform. The platform's length is 12 feet.
a. 400 m
b. 450 m
c. 560 m
d. 600 m
Answer: A
Explanation:
Let the first train's length be x metres.The length of the second train is then ( x/2 ) metres.
(48 + 42) kmph = (90 x 5/18) m/sec = 25 m/sec Relative speed = (48 + 42) kmph.As a result, [x + (x/2)]/25 = 12 or 3x/2 = 300 or x = 200.As a result, the initial train's length is 200 metres.Let the platform's length be y metres.The first train's speed is ( 48 x 5/18 ) m/sec, or 40/3 m/sec.
As a result, (200 + y) x 3/40 = 45.=> 1800 = 600 + 3y=> 400 m for y.
30. On a straight path, the two stations A and B are 110 kilometres apart. At 7 a.m., one train departs from A. and moves at a speed of 20 kmph in the direction of B At 8 a.m., another train departs from B. It is travelling at a speed of 25 kmph in the direction of A. When are they going to meet?
a. 9 a.m.
b. 10 a.m.
c. 10.30 a.m.
d. 11 a.m.
Answer: B
Explanation:
Assume they meet at 7 a.m., x hours later.A's distance travelled in x hours equals 20x kilometres.B's distance travelled in (x - 1) hours is 25(x - 1) kilometres.As a result, 20x + 25(x - 1) = 110, implying that 45x = 135 and x = 3.As a result, they convene at 10 a.m.
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