Distance- Aptitude Questions and Answers | Online MCQ Aptitude Test Distance- Distance Aptitude Questions and answers- This is a Distance aptitude questions and answers section with an explanation for various interviews, competitive examinations, and admission tests. Answers to the most recent Distance aptitude questions. Aptitude for Distance In the Quantitative Aptitude test, multiple-choice questions are frequently asked. Candidates can effortlessly take numerous competitive exams such as SAIL, RAIL, GAIL, BHEL, NTPC, ONGC, BEL, IOCL, SBI, CAT, etc. by practising the Distance Quiz Online Test Question and Answers. So, let's have a look at the Time, Speed, and Distance MCQs to see how well you do. This is a new Distance Aptitude Online Test that will help you prepare for your forthcoming bank exam. This Distance MCQ quiz contains essential questions which match the exam pattern of the banking exam like IBPS, so make sure that and attempt the Distance Aptitude Online Test as much as required to check your preparation level.
Distance Quiz Details
Quiz Name
Distance
Category
Online Aptitude Test
Number of Questions
30
Time
30 Minutes
Exam Type
MCQ (Multiple Choice Questions)
Distance Online Test
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Distance Online Test - Start Now
1. On both sides of a lighthouse, two ships are cruising in the water. From the ships, the angle of elevation of the top of the lighthouse is 30° and 45°, respectively. The distance between the two ships is: If the lighthouse is 100 metres high, the distance between the two ships is:
a. 173 m
b. 200 m
c. 273 m
d. 300 m
Answer: C
Explanation:
Assume AB is the lighthouse and C and D are the ship positions.Then ADB = 45°, ACB = 30°, and AB = 100 m.AB/AC = tan 30° = 1/ ROOT 3, AC = AB x 3 = 100/ ROOT3 m AB/AC = tan 30° = 1/ ROOT 3 m,AB/AD = tan 45° = 1 AD = AB = 100 m AB/AD = tan 45° = 1 AD = AB = 100 m,(100/ ROOT3 + 100) m = 100 ROOT 3 + 1) = (100 x 2.73) m = 273 m CD = (AC + AD) = (100/ ROOT3 + 100) m = 100 ROOT 3 + 1) = (100 x 2.73) m = 273 m
2. A guy standing at point P is looking up at the top of a tower, which is at a 30° angle with the man's eye. The man travels a short distance towards the tower to observe its summit, and the elevation angle changes to 60 degrees. What is the length of the distance between the tower's base and point P
a. 4 ROOT3 units
b. 8 units
c. 12 units
d. Data inadequate
Answer: D
Explanation:
One of the letters AB, AD, or CD must have been given.As a result, the data is insufficient.
3. A ladder lying against a wall has a 60-degree angle of elevation, and the ladder's foot is 4.6 metres distant from the wall. The ladder's length is as follows:
a. 2.3 m
b. 4.6 m
c. 7.8 m
d. 9.2 m
Answer: D
Explanation:
Assume that AB represents the wall and BC represents the ladder.Then ACB = 60° and AC = 4.6 m are calculated. AC/BC = cos 60° = 1/2 , BC = 2 x AC = (2 x 4.6) m = 9.2 m
4. A tower is 203 metres away from a 1.6 metre height spectator. From his eye to the top of the tower, the angle of elevation is 30 degrees. The tower stands at the following height:
a. 21.6 m
b. 23.2 m
c. 24.72 m
d. None of these
Answer: A
Explanation:
Assume the observer is AB, and the tower is CD.BE CD should be drawn,CE = AB = 1.6 m, BE = AC = 203 m, and so on, DE/BE = tan 30° = 1/ ROOT 3 DE =20 ROOT 3/ ROOT 3 m = 20 m DE/BE = tan 30° = 1/ ROOT 3 DE =20 ROOT 3/ ROOT 3 m = 20 m, CD = CE + DE = (1.6 + 20) m = 21.6 m
5. The angle of elevation of the top tower from a point P on flat ground is 30°. If the tower is 100 metres tall, the distance between point P and the tower's foot is:
a. 149 m
b. 156 m
c. 173 m
d. 200 m
Answer: C
Explanation:
Assume the tower is AB.APB = 30° and AB = 100 m, respectively.ROOT 3 AP = (AB x ROOT3) m = 100 ROOT 3 m = (100 x 1.73) m = 173 m AB/ AP = tan 30° = 1/ ROOT 3, AP = (AB x ROOT3) m = 100 ROOT 3 m = (100 x 1.73) m = 173 m
6. When the length of a tree's shadow is three times its height, the sun's angle of elevation is
a. 30°
b. 45°
c. .60°
d. .90°
Answer: A
Explanation:
Assume that AB represents the tree and AC represents its shadow.Let's say ACB = THETA.After that, AC/AB = ROOT 3 cot = ROOT 3= 30 degrees.
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